Lab0

Thorin
---

1.1 Challange1

在kali-linux-2023上进行

1.1.1 路径相关命令

cd filename
cd ..  #上一级路径
cd ~   #home
cd .   #当前路径

1.1.2 文件目录操作命令

ls -a #列出所有文件和目录
ls -l #列出详细信息
touch file #创建文件
mkdir dir  #创建目录

1.1.3 文件内容查看命令

cat file 
head -n lines file #显示前lines行
tail -n lines file #显示后lines行

1.1.4 其他命令

whoami   #获取当前用户
date     #获取当前时间
ps       #显示进程信息

1.2 challenge2

1.2.1 解释代码

#!/usr/bin/python3

data = input("give me your string: ") #data存储输入
print("length of string:", len(data)) #输出data长度
  
data_old = data                       #存储未更新的data
data_new = ""                         
for d in data:                         
    if d in 'abcdefghijklmnopqrstuvwxyz':    #大小写互换后存入data_new
        data_new += chr(ord(d) - 32)
    elif d in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ':
        data_new += chr(ord(d) + 32)
    else:
        data_new += d                       #非字母不修改

print("now your string:", data_new)          #输出结果

1.2.2calculator

import socket

lPOST = '10.214.160.13'
rHOST = 11002
client_socket = socket.socket()
client_socket.connect((lPOST, rHOST))

while 1:
    data1 = client_socket.recv(1024)
    data2 = client_socket.recv(1024)
    print(data1)
    print(data2)
    new_data = data2[:-2]
    print(new_data)
    client_socket.send((format(eval(new_data))+'\n').encode())
    print(format(eval(new_data)).encode())

AAA{melody_loves_doing_calculus_qq_qun_386796080}

2.1 Crypto

for i in range(4):
    for j in range(4):
        result[i][j] = s[i][j] ^ k[i][j]
for i in range(4):
     for j in range(4):
         result[i][j] = inv_s_box[s[i][j]]

AAA{AE5_aEs_a1s}

3.1 Misc

AAA{wELCOm3_7o_CTf_5umMeR_c0uR5E_2023}

AAA{gr3@t_J08!_1et’5_P1@y_m1S C_TOG3Th3R}